IPP> "IPP" == "DPA"

IPP> "IPP" == "DPA"

IPP> "IPP" == "DPA"

JK Martin jkm at underscore.com
Thu Mar 20 05:27:30 EST 1997


After reviewing Tom Hasting's most recent issues document, it is
really starting to appear that "IPP" is simply the 1990's name
for "DPA" in terms of scope and complexity.


Does anyone else out there share this view?


	...jay



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